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Two alkenes, A and B, have the same molecular formula C5H10, give the same alkane when treated with H2/Pd and the same alcohol when treated with H/H2O. However, they give different alcohols when treated with BH3: THF followed by H2O2/ΘOH. Treatment of alkene A with O3 followed by Zn/H2O gave two carbonyl compounds C (C3H6O) and D (C2H4O) that showed the following NMR data. 

C δ 2.07 singlet

D δ 9.79 quartet (1H) and δ 2.21 doublet

Give structures for A, B, C and D


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